A model train with a mass of #4 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #21 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-07-20T05:52:34

The change in centripetal force is #=0.02357N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=4kg#

speed, #v=0.06ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=4*0.06^2/0.32=0.045N#

#F_2=mv^2/r_2=4*0.06^2/0.21=0.06857N#

#DeltaF=0.06857-0.045=0.02357N#