A model train with a mass of #4 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #21 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jul 20, 2017

Answer:

The change in centripetal force is #=0.02357N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=4kg#

speed, #v=0.06ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=4*0.06^2/0.32=0.045N#

#F_2=mv^2/r_2=4*0.06^2/0.21=0.06857N#

#DeltaF=0.06857-0.045=0.02357N#