A model train with a mass of #4 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #56 cm# to #27 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-22T11:47:19

The change in centripetal force is #=0.0276N#

The centripetal force is

#F=(mv^2)/r#

#m=mass=4kg#

#v=0.06ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=4*0.06^2/0.56=0.0257N#

#F_2=4*0.06^5/0.27=0.0533N#

#DeltaF=0.0533-0.0257=0.0276N#