A model train, with a mass of #5 kg#, is moving on a circular track with a radius of #9 m#. If the train's rate of revolution changes from #5 Hz# to #9 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Jul 3, 2017

Answer:

The centripetal force changes by #=28.424kN#

Explanation:

The centripetal force is

#F=mr omega^2#

The mass is #m=5kg#

The radius #r=9m#

The change in angular velocity is

#Delta omega=(9-5)*2pi=(8pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=5*9*(8pi)^2#

#=28424N#