A model train with a mass of #6 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #12 cm# to #16 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Dec 25, 2017

Answer:

The change in centripetal force is #=0.08N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is of the train #m=6kg#

The velocity is #v=0.08ms^-1#

The radii are

#r_1=0.12m#

and

#r_2=0.16m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=6*0.08^2/0.12=0.32N#

#F_2=6*0.08^2/0.16=0.24N#

#DeltaF=0.32-0.24=0.08N#