A model train, with a mass of #6 kg#, is moving on a circular track with a radius of #7 m#. If the train's rate of revolution changes from #1 Hz# to #2 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Nov 18, 2016

Answer:

The centripetal force applied is #F_c=1654.8#Newtons.

Explanation:

Centripetal force is defined as #F_c=mromega^2#.
Angular acceleration #omega= 2pi#(change in frequency)
#=>omega=2pi(nu_2-nu_1)#.
Now the centripetal force becomes
#F_c=mr[2pi(nu_2-nu_1)]^2#.
#F_c= 4mrpi^2(nu_2-nu_1)^2#
Substituting the given values we get,
#F_c= 4(2kg)(7m)(3.14)^2[(2Hz)-(1Hz)]^2#
#:. F_c = 1654.8#Newtons.