Question

A model train, with a mass of `6 kg`, is moving on a circular track with a radius of `7 m`. If the train's rate of revolution changes from `1 Hz` to `2 Hz`, by how much will the centripetal force applied by the tracks change by?

Answer 1

The centripetal force applied is `F_c=1654.8`Newtons.

Explanation:

Centripetal force is defined as `F_c=mromega^2`.
Angular acceleration `omega= 2pi`(change in frequency)
`=>omega=2pi(nu_2-nu_1)`.
Now the centripetal force becomes
`F_c=mr[2pi(nu_2-nu_1)]^2`.
`F_c= 4mrpi^2(nu_2-nu_1)^2`
Substituting the given values we get,
`F_c= 4(2kg)(7m)(3.14)^2[(2Hz)-(1Hz)]^2`
`:. F_c = 1654.8`Newtons.