A model train with a mass of #7 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #24 cm# to #36 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Apr 5, 2017

Answer:

The centripetal force changes by #=0.14N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=7kg#

speed, #v=0.12ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=7*0.12^2/0.24=0.42N#

#F_2=7*0.02^2/0.36=0.28N#

#DeltaF=F_1-F_2=0.42-0.28=0.14N#