A model train with a mass of #8 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #21 cm# to #120 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Apr 8, 2017

Answer:

The change in centripetal force is #=0.025N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=8kg#

speed, #v=0.09ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=8*0.09^2/0.21=0.31N#

#F_2=8*0.09^2/1.20=0.054N#

#DeltaF=0.31-0.054=0.025N#