A model train with a mass of #8 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #27 cm# to #72 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Nov 7, 2017

Answer:

The change in centripeta force is #=0.15N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(8)kg#

The speed, #v=(0.09)ms^-1#

The radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=8*0.09^2/0.27=0.24N#

#F_2=mv^2/r_2=8*0.09^2/0.72=0.09N#

#DeltaF=0.24-0.09=0.15N#