A model train with a mass of #8 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #180 cm# to #63 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Dec 1, 2017

Answer:

The change in centripetal force is #=0.067N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is #m=8kg#

The velocity is #v=0.09ms^-1#

The radii are

#r_1=1.80m#

and

#r_2=0.63m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=8*0.09^2/1.8=0.036N#

#F_2=8*0.09^2/0.63=0.103N#

#DeltaF=0.103-0.036=0.067N#