A model train, with a mass of #8 kg#, is moving on a circular track with a radius of #1 m#. If the train's rate of revolution changes from #2/5 Hz# to #5/6 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
May 7, 2017

Answer:

The centripetal force changes by #=14.8N#

Explanation:

The centripetal force is

#F=mr omega^2#

mass is #m=8kg#

radius #r=1m#

#Delta omega=(5/6-2/5)*2pi=(13/30pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=8*1*(13/30pi)^2#

#=14.8N#