A model train, with a mass of #8 kg#, is moving on a circular track with a radius of #1 m#. If the train's rate of revolution changes from #3/5 Hz# to #5/6 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
May 14, 2018

Answer:

The change in centripetal force is #=105.6N#

Explanation:

The centripetal force is

#F=(mv^2)/r=mromega^2N#

The mass of the train, #m=(8)kg#

The radius of the track, #r=(1)m#

The frequencies are

#f_1=(3/5)Hz#

#f_2=(5/6)Hz#

The angular velocity is #omega=2pif#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mromega_1^2=mr*(2pif_1)^2=8*1*(2pi*3/5)^2=113.7N#

#F_2=mromega_2^2=mr*(2pif_2)^2=8*1*(2pi*5/6)^2=219.3N#

#DeltaF=|F_2-F_1|=219.3-113.7=105.6N#