A model train, with a mass of #8 kg#, is moving on a circular track with a radius of #1 m#. If the train's rate of revolution changes from #3/5 Hz# to #5/4 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 24, 2017

Answer:

The change in centripetal force is #=133.4N#

Explanation:

The centripetal force is

#F=mr omega^2#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=8*1*((5/4-3/5)2pi)^2#

#=8*13^2/100*pi^2#

#=133.4N#