A model train with a mass of #9 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #45 cm# to #30 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jul 2, 2017

Answer:

The change in centripetal force is #=0.225N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=9kg#

speed, #v=0.15ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=9*0.15^2/0.45=0.45N#

#F_2=mv^2/r_2=9*0.15^2/0.30=0.675N#

#DeltaF=0.675-0.45=0.225N#