A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 2, 2017

Answer:

The change in centripetal force is #=0.22N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=9kg#

#v=0.18ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=9*0.18^2/0.32=0.91N#

#F_2=9*0.18^2/0.42=0.69N#

#DeltaF=0.91-0.69=0.22N#