A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #24 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Nov 21, 2016

Answer:

The centripetal force applied by the tracks change is #F_c=1.62N#.

Explanation:

Centripetal force #F_c=mv^2/r#
As we know change in force '#DeltaF_c#' is inversely proportional to the change in the radius '#Deltar#'.
So #Deltar=42cm-24cm=18cm#
Conversion into metres for SI units #:.Deltar=18xx10^-2metre#.
Similarly to the velocity#:.v=18xx10^-2m//s#.
Substituting these values in above force equation we get,
#F_c={(9kg)(18xx10^-2m//s)^2}/(18xx10^-2m)=1.62N#.