A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #66 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jun 25, 2017

Answer:

The centripetal force changes by #=0.25N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=9kg#

speed, #v=0.18ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=9*0.18^2/0.66=0.44N#

#F_2=mv^2/r_2=9*0.18^2/0.42=0.69N#

#DeltaF=0.69-0.44=0.25N#