A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #36 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Aug 1, 2018

Answer:

The change in centripetal force is #=0.12N#

Explanation:

The centripetal force is

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=9kg#

The velocity of the train is #v=0.18ms^-1#

The radii of the tracks are

#r_1=0.36m#

and

#r_2=0.42m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#||F_1||=9*0.18^2/0.36=0.81N#

#||F_2||=9*0.18^2/0.42=0.69N#

#DeltaF=|F_1-F_2|=0.81-0.69=0.12N#