A neon gas in a sign has a volume of 42.5 L at 25 °C and 3.5 kPa. What is the mass of neon?

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A neon gas in a sign has a volume of 42.5 L at 25 °C and 3.5 kPa. What is the mass of neon?

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Answer 1 · 2016-06-04T16:53:58

Approx. $1 \cdot g$ $1*g$ .

Explanation:

$n = \frac{P V}{R T}$ $n=(PV)/(RT)$ $=$ $=$ $\frac{3.5 \times k P a \times 42.5 \cdot L}{8.314 \cdot L \cdot k P a \cdot K^{- 1} \cdot m o l^{- 1} \times 298 \cdot K}$ $(3.5xxkPaxx42.5*L)/(8.314*L*kPa*K^-1* mol^-1xx298*K)$

$=$ $=$ $6.00 \times 10^{- 2} \cdot m o l$ $6.00xx10^-2*mol$

Thus $mass neon$ $"mass neon"$ $=$ $=$ $6.00 \times 10^{- 2} \cdot m o l \times 20.18 \cdot g \cdot m o l^{- 1}$ $6.00xx10^-2*molxx20.18*g*mol^-1$ $=$ $=$ $? ? g$ $??g$

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A neon gas in a sign has a volume of 42.5 L at 25 °C and 3.5 kPa. What is the mass of neon?

1 Answer

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