# A nugget of gold displaces 0.950 cm^3 of water. If a jeweler offers $8.00/g for the nugget, how much money is the nugget worth? (density of gold = 19.3 g/cm^3)? ##### 1 Answer Jan 31, 2017 #### Answer: It is worth more than the jeweller offers......... #### Explanation: $\rho , \text{density"="mass"/"volume}$And thus $19.3 \cdot g \cdot \cancel{c {m}^{-} 3} \times 0.950 \cdot \cancel{c {m}^{3}} = \text{mass of the nugget}$$=$$18.3 \cdot g$. The jeweller would offer 18.3*gxx$8=00*g^-1~=$150-00. The current spot price for gold is $\text{39-00 USD} \cdot {g}^{-} 1\$. I would tell that jeweller that he is having a laugh............in an Arthur Daleyesque manner.

I had a friend who dealt in precious metals, and he said that when the gold price took off, a lot of people (sadly) cashed in their gold jewellery just for the price of the metal. He and his friends bought some beautiful pieces of antique jewellery for the (discounted) price of the gold, but also for the workmanship and intrinsic beauty of the jewellery.