A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?

1 Answer
anor277
Jul 8, 2016

#"Density", rho# #=# #"Mass"/"Volume"# #=# #(521*g)/(27.0*mL)=??#

Explanation:

#"Density", rho# #=# #"Mass"/"Volume"# #=# #(521*g)/(77.0*mL-50.0*mL)~=19*g*mL^-1#

Just to add, that the density of gold is so large is the reason why you see those pictures of old, grizzled prospectors, panning for gold by river beds. The gold sinks to the bottom of the pan, and you can decant off the silt, and the water, hopefully leaving the gold behind.

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My god, what a grub...hasn't he heard of barbers and razors? They probably don't exist out in the Yukon or Bathurst at that time....

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