A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?

Jul 8, 2016

$\text{Density} , \rho$ $=$ $\text{Mass"/"Volume}$ $=$ (521*g)/(27.0*mL)=??
$\text{Density} , \rho$ $=$ $\text{Mass"/"Volume}$ $=$ $\frac{521 \cdot g}{77.0 \cdot m L - 50.0 \cdot m L} \cong 19 \cdot g \cdot m {L}^{-} 1$