A parabola has an axis of symmetry x=5 and passes through the point (-5,6). How do you find another point that lies on the graph of the parabola?
1 Answer
Dec 28, 2017
Explanation:
#"the point "(-5,6)" is 10 units left of the axis of "#
#"symmetry"#
#"that is x-coordinate is "5-(-5)=10larr#
#"due to the symmetry another point will be 10 units"#
#"to the right of the axis of symmetry"#
#"that is x-coordinate is "5+10=15rarr#
#rArr"another point is "(15,6)#
#"the y-coordinates do not change"#
