A parallelogram has sides A, B, C, and D. Sides A and B have a length of #3 # and sides C and D have a length of # 9 #. If the angle between sides A and C is #pi/12 #, what is the area of the parallelogram?

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Answer 1 · 2017-03-27T11:16:18

The area of the parallelogram is #6.99 (2dp) sq. unit#

Sides of parallelogram are #A=B=3 , C=D=9 #

Included angle between sides #A & C# is #theta = pi/12=180/12=15^0#

The area of the parallelogram is #A_p= A*C*sin theta = 3*9*sin15 =6.99 (2dp) #sq.unit [Ans]