A parallelogram has sides A, B, C, and D. Sides A and B have a length of #5 # and sides C and D have a length of # 2 #. If the angle between sides A and C is #(3 pi)/8 #, what is the area of the parallelogram?

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Answer 1 · 2018-02-16T03:25:10

Area of a parallelogram #A = b * a sin theta ~~ color(green)( 9.2388# sq units

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Area of a parallelogram #A = b * a sin theta# as May be seen from the above figure.

Given #b = 5, a = 2, theta = (3pi)/8#

#A = 5 * 2 * sin ((3pi)/8) = 10 sin ((3pi)/8) ~~ color(green)( 9.2388# sq units