A parallelogram has sides A, B, C, and D. Sides A and B have a length of #6 # and sides C and D have a length of # 2 #. If the angle between sides A and C is #(3 pi)/4 #, what is the area of the parallelogram?

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Answer 1 · 2016-12-24T11:06:30

The area of parallelogram is #8.49(2dp) # sq.unit.

The area of parallelogram of parallal sides #A=B=6 # and another parallal sides #C=D=2 # and an angle between

#A and C , theta= (3pi)/4 = 3*180/4=135^0# is

#A_p=A*C*sin theta = 6*2*sin135=8.49(2dp) #sq.unit [Ans]