A parallelogram has sides A, B, C, and D. Sides A and B have a length of #6 # and sides C and D have a length of # 3 #. If the angle between sides A and C is #(3 pi)/4 #, what is the area of the parallelogram?

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Answer 1 · 2018-05-22T06:29:11

Area of parallelogram #A_p = 9sqrt2 = 12.73# sq units

Formula for area of a parallelogram #A_p = a b sin theta#

A_p Area of parallelogram, a = lengths of sides A & B, b = lengths of sides C & D

#a = 6, b = 3, theta = (3pi)/4#

#A_p = 6 * 3 * sin ((3pi)/4)#

#A_p = 18/sqrt2 = 9sqrt2 = 12.73# sq units