A piece of metal ore weighs 8.250 * 10^-3 kg. When a student places it into a graduated cylinder containing water, the liquid level rises from 21.25 mL to 26.47 mL. What is the density of the ore?

$\text{Density}$, $\rho$ $=$ $\text{Mass"/"Unit volume}$. The mass of the ore is $8.25$ $g$
$\rho$ $=$ $\text{Mass"/"Volume displaced}$ $=$ $\frac{8.25 \cdot g}{\left(26.47 - 21.25\right) \cdot m L}$ $=$ ??g*mL^-1