A piece of titanium metal has a mass of 67.5 g and a volume of 15 cm^3. What is the density of titanium?

Aug 20, 2016

$\text{Density, "rho="mass"/"volume}$, so $\rho = \text{a bit over 4 g} \cdot c {m}^{-} 3$
$\rho$ $=$ $\frac{67.5 \cdot g}{15 \cdot c {m}^{3}}$ $=$ ??g*cm^-3. Should iron float?
Note that the units $c {m}^{3}$ and $m L$ are used interchangeably, and often cause a bit of angst. $1 \cdot c {m}^{3}$ $=$ $1 \cdot m L$ indisputably.
Why? Well $1 \cdot c {m}^{3}$ $=$ ${\left(1 \times {10}^{-} 2 \cdot m\right)}^{3}$ $=$ $1 \times {10}^{-} 6 \cdot {m}^{3}$ $=$ $1 \times {10}^{-} 3 \cdot L$ $=$ $1 \cdot m L$ because there are $1000 \cdot L$ in a $\text{cubic metre}$.