Question

A projectile is shot from the ground at a velocity of `1 m/s` and at an angle of `(pi)/2`. How long will it take for the projectile to land?

Answer 1

`v_f = v_i + at`
`pi/2` is straight up
`0 = 1 - (9.81 xxt)` and `t= 1/9.81 ~~ .1 s`

Explanation:

graph{-(50x)^2 +5 [-1, 1, 0, 5]}
Observe the arbitrary graph that I provided. It show that the projectile will climb up and come down after it reach maximum height. At maximum height the speed `v_f = 0` knowing this write
`v_f = v_i + at` we know that `v_i = 1m/s; and a = g = -9.81 m/s^2`
Thus `0 = 1 - (9.81 xxt)` and `t= 1/9.81 ~~ .1 s`