A projectile is shot from the ground at a velocity of #1 m/s# and at an angle of #(pi)/2#. How long will it take for the projectile to land?

1 Answer
Jan 25, 2016

Answer:

#v_f = v_i + at#
#pi/2# is straight up
#0 = 1 - (9.81 xxt) # and #t= 1/9.81 ~~ .1 s#

Explanation:

graph{-(50x)^2 +5 [-1, 1, 0, 5]}
Observe the arbitrary graph that I provided. It show that the projectile will climb up and come down after it reach maximum height. At maximum height the speed #v_f = 0# knowing this write
#v_f = v_i + at# we know that #v_i = 1m/s; and a = g = -9.81 m/s^2#
Thus #0 = 1 - (9.81 xxt) # and #t= 1/9.81 ~~ .1 s#