A projectile is shot from the ground at a velocity of 19 m/s and at an angle of (pi)/2. How long will it take for the projectile to land?

1 Answer
Dec 28, 2015

The projectile takes 3.87s to land.

Explanation:

In this particular case there is only the vertical component of motion (because angle is 90°). We consider the equation s=vt-1/2at^2 and assume s=0. So t(v-1/2at)=0 and t=2v/g=(2*19m/s)/(9.81m/s^2)=3.87s.
That's all.