A projectile is shot from the ground at a velocity of #19 m/s# at an angle of #pi/4#. How long will it take for the projectile to land?

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Answer 1 · 2017-01-14T19:01:58

The time is #=2.74s#

Vertical motion #uarr^+#

#u=19sin(pi/4)ms^-1#

#a=-9.8ms^-2#

#y=ut+1/2at^2#

#0=19sin(pi/4)t-1/2*9.8*t^2#

#t=0# or #t=19sin(pi/4)/4.9=2.74s#

Horizontal motion #rarr^+#

#u=19cos(pi/4)ms^-2#

#x=2.74*19*cos(pi/4)=36.84m#