A projectile is shot from the ground at a velocity of 2 m/s and at an angle of (2pi)/3. How long will it take for the projectile to land?

Oct 12, 2017

$\frac{2 \sqrt{3}}{10}$ seconds

Explanation:

T = (2u sin θ) / g

T = (2 × 2 ms^-1 sin ((2 π)/3)) / (10 ms^-2)

T = (4 × sqrt(3)/2) / (10) s

$T = \frac{2 \sqrt{3}}{10}$ $\textrm{\sec o n \mathrm{ds}}$