A projectile is shot from the ground at a velocity of #2 m/s# and at an angle of #(pi)/2#. How long will it take for the projectile to land?

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Answer 1 · 2018-04-11T12:23:52

The time is #=0.41s#

Resolving in the vertical direction #uarr^+#

The initial velocity is #u=(2)sin(pi/2)=2ms^-1#

The acceleration due to gravity is #a=-g=-9.8ms^-2#

Apply the equation of motion

#s=ut+1/2at^2#

#s=0m#

Therefore,

#0=2t-1/2*9.8*t^2#

#4.9t^2-2t=0#

#t(4.9t-2)=0#

#t=0# which is the initial conditions

#t=(2)/4.9=0.41s#