A projectile is shot from the ground at a velocity of #2 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

1 Answer
Mar 27, 2017

Answer:

The time to land #=0.4s#

Explanation:

Solving in the vertical direction #uarr^+#

#u=u_0sintheta=2sin(5/12pi)ms^-1#

#a=-g=-9.8ms^-2#

#v=0# at the maximum height

We apply the equation

#v=u+at#

#0=2sin(5/12pi) - g*t#

#t=(2sin(5/12pi))/g=0.2s#

This is the time to reach the maximum height

The time to land #=0.2*2=0.4s#