A projectile is shot from the ground at a velocity of #2 m/s# at an angle of #pi/12#. How long will it take for the projectile to land?

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Answer 1 · 2017-12-27T07:58:39

The time is #=0.106s#

Resolving in the vertical direction #uarr^+#

The initial velocity is #u_0=2sin(1/12pi)ms^-1#

The time to reach the greatest height is #=ts#

The acceleration due to gravity is #g=9.8ms^-2#

Applying the equation of motion

#v=u+at=u- g t #

The time is #t=(v-u)/(-g)=(0-2sin(1/12pi))/(-9.8)=0.053s#

The time taken to land is twice the time to reach the greatest height

#T=2t=2*0.053=0.106s#