# A projectile is shot from the ground at a velocity of 25 m/s and at an angle of (2pi)/3. How long will it take for the projectile to land?

Nov 16, 2016

Time of flight $T = \left(2 u \sin \theta\right) / g$
We consider acceleration due to the gravity $' g ' = 9.8 m / {s}^{2}$.
$T = \left[2 \times 25 m / s \times \sin \left(2 \pi / 3\right)\right] / 9.8 m / {s}^{2}$.
$\therefore T = 4.41 \sec o n \mathrm{ds}$.