# A projectile is shot from the ground at a velocity of 36 m/s and at an angle of (pi)/2. How long will it take for the projectile to land?

Here actually the projection is done vertically upwards,so time of flight will be $T = \frac{2 u}{g}$ where, $u$ is the velocity of projection.
Given, $u = 36 m {s}^{-} 1$
So, T=(2×36)/9.8=7.35 s