# A projectile is shot from the ground at a velocity of 36 m/s and at an angle of (5pi)/6. How long will it take for the projectile to land?

Apr 2, 2016

${t}_{e} \cong 3 , 67 \text{ s}$

#### Explanation:

$\text{given data:}$

v_i=36" "m/s" "alpha=(5pi)/6" "t_e=?
${v}_{i} : \text{initial velocity}$
$\alpha : \text{projectile angle}$
${t}_{e} : \text{elapsed time for the projectile}$

$\text{formula : } {t}_{e} = \frac{2 \cdot {v}_{i} \cdot \sin \alpha}{g}$

$\sin \left(\frac{5 \pi}{6}\right) = 0 , 5$

${t}_{e} = \frac{2 \cdot 36 \cdot 0 , 5}{9 , 81}$

${t}_{e} \cong 3 , 67 \text{ s}$