Question

A projectile is shot from the ground at a velocity of `4 m/s` at an angle of `(5pi)/12`. How long will it take for the projectile to land?

Answer 1

`x_(max)~=0,408" m"`

Explanation:

`theta=(5cancel(pi))/12*180/cancel(pi)`
`theta=75 ^o`
`g=9,82 m/s^2`
`sin 2theta=150 ^o=sin 30^o=0,5`
`x_(max)=(v_i^2*sin 2theta)/(2*g)`
`x_(max)=(4^2*0,5)/(2*9,81)`
`x_(max)=(16 *0,5)/(19,62)`
`x_(max)=8/(19,62)`
`x_(max)~=0,408" m"`