A projectile is shot from the ground at a velocity of #5 m/s# at an angle of #(5pi)/12#. How long will it take for the projectile to land?

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Answer 1 · 2017-01-30T08:18:57

The answer is #0.99 s#

Resolving in the vertical direction #uarr^+#

#u=5sin(5/12pi) ms^-1#

#a=-g ms^-2#

#s=0m#

We use the equation

#s=ut+1/2at^2#

#0=5sin(5/12pi)*t-g/2t^2#

#t(5sin(5/12pi)-g/2t)=0#

Therefore,

#t=0#, this is when the projectile is shot

and

#5sin(5/12pi)-g/2t=0#

#t=10/gsin(5/12pi)#

#t=10/9.8sin(5/12pi)=0.99s#