# A projectile is shot from the ground at a velocity of 8 m/s at an angle of pi/6. How long will it take for the projectile to land?

Oct 24, 2016

The time is $0.8$s

#### Explanation:

Use the formula
$s = {u}_{o} t - \left(\frac{1}{2}\right) g {t}^{2}$

$s = 0$
${u}_{o} = 8 \sin \left(\frac{\pi}{6}\right)$
and $t$ is the time

$t = 0$

or $t = \left(8 \cdot 2\right) \sin \frac{\frac{\pi}{6}}{g} = 16 \sin \frac{\frac{\pi}{6}}{g}$

$\sin \left(\frac{\pi}{6}\right) = \frac{1}{2}$ and $g = 10$
So $t = \left(\frac{16}{10}\right) \frac{1}{2} = 0.8 s$