# A rectangle has width 22 in and length 18 in. How do you find the length of another rectangle of equal area, if the width is 20 in?

Mar 11, 2018

The length of rectangle $2$ is $19.8$ in.

#### Explanation:

Area of the rectangle $1$ is ${A}_{1} = 22 \cdot 18$ sq.in

Let the length of rectangle $2$ be $x$ in.

Area of the rectangle $2$ is ${A}_{2} = 20 \cdot x$ sq.in

${A}_{1} = {A}_{2} \therefore 20 \cdot x = 22 \cdot 18 \therefore x = \frac{22 \cdot 18}{20} \mathmr{and} x = 19.8$ in.

The length of rectangle $2$ is $19.8$ in. [ans]