# A rectangle with perimeter 104 cm has a width of 18 cm less that its length. What is the area?

Feb 22, 2016

Area $= 595 c {m}^{2}$

#### Explanation:

Let the length of the rectangle be $= l$
Then its width $= l - 18$

Its perimeter is $= 104 c m$

2(width + length)$= 104$

$2 \left(\left(l - 18\right) + l\right) = 104$
$2 \left(l - 18 + l\right) = 104$
$2 l - 36 + 2 l = 104$
$4 l = 104 + 36$
$l = \frac{140}{4} = 35$
$w = 35 - 18 = 17$
Area$= w \times l = 17 \times 35 = 595 c {m}^{2}$