# A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?

Area of the triangle $= 24 \text{ }$square units

#### Explanation:

By inspection the ${90}^{\circ}$ angle is at (0, 0) then one side to the right along x-axis $= 6 \text{ }$units. Another side from the origin (0,0) going up $= 8 \text{ }$units.
Therefore, altitude $= 8$
and base $= 6$

$A r e a = \frac{1}{2} b h$
$A r e a = \frac{1}{2} \cdot 6 \cdot 8$
$A r e a = 24$

God bless....I hope the explanation is useful.

The Perimeter $P = 24 \text{ }$units

#### Explanation:

The hypotenuse $c$ of the right triangle is
$c = \sqrt{{6}^{2} + {8}^{2}} = \sqrt{36 + 64} = \sqrt{100} = 10 \text{ }$

Perimeter $P = a + b + c = 6 + 8 + 10 = 24 \text{ }$units

God bless...I hope the explanation is useful.