# A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas?

Sep 17, 2016

The sample of gas contains 1.3 moles of gas.

#### Explanation:

Use the ideal gas law as shown below.

$P = \text{121.59 kPa}$
$V = \text{31 L}$
$T = \text{360 K}$
$R = 8.3144598 \text{L kPa K"^(-1) "mol"^(-1)}$

Rearrange the equation to isolate $n$, plug in the known values, and solve.

$n = \frac{P V}{R T}$

n=(121.59cancel"kPa"xx31cancel"L")/(8.3144598cancel"L kPa K"^(-1) "mol"^(-1)xx360cancel"K")="1.3 mol" (rounded to two significant figures)