A sample of helium gas occupies 14.7 L at 23°C and .956 atm. What volume will it occupy at 40°C and 1.20 atm?

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Answer 1 · 2016-12-17T04:09:32

#(P_1V_1)/T_1=(P_2V_2)/T_2#

#(P_1V_1)/T_1=(P_2V_2)/T_2#, which is the combined gas law? Temperature is specified to be on the #"Absolute scale"#.

So, #V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)#

#=# #(0.956*atmxx14.7*Lxx313*K)/(300*Kxx1.20*atm)#

I get an answer (clearly, why?) in #"litres"#.