A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #18 # and the height of the cylinder is #1 #. If the volume of the solid is #21 pi#, what is the area of the base of the cylinder?

1 Answer
Bio
Mar 22, 2016

#3pi ~~ 9.425#

Explanation:

The volume of the cylinder is given by its height multiplied by the area of its circular base.

#V_"cylinder" = pi * r^2 * h_"cylinder"#

  • #h_"cylinder" = 1# in this question.

The volume of a cone is given by a third of its height multiplied by the area of its circular base.

#V_"cone" = 1/3 * pi * r^2 * h_"cone"#

  • #h_"cone" = 18# in this question.
  • The variable #r# is reused as the cone has the same radius as the cylinder.

The volume of the entire solid is

#V_"solid" = V_"cylinder" + V_"cone"#

#= pi * r^2 * h_"cylinder" + 1/3 * pi * r^2 * h_"cone"#

#= pi * r^2 * (h_"cylinder" + 1/3 h_"cone")#

#= pi * r^2 * (1 + 1/3 xx 18)#

Now it becomes a simple matter to solve for the base area of the cylinder, which is just #pi r^2#.

#pi * r^2 = V_"solid"/(1 + 1/3 xx 18)#

#= (21pi)/7#

#= 3pi#

#~~ 9.425#

Related questions
See all questions in Volume of Solids
Impact of this question
1050 views around the world
You can reuse this answer
Creative Commons License