A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $36$ and the height of the cylinder is $5$ . If the volume of the solid is $18 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2017-03-06T07:43:03

The area of the base is $=3.33u^2$

Let $a=$ area of the base

Volume of cone is $V_(co)=1/3*a*h_(co)$

Volume of cylinder is $V_(cy)=a*h_(cy)$

Total volume

$V=V_(co)+V_(cy)$

$V=1/3ah_(co)+ah_(cy)$

$18pi=a(1/3*36+5)$

$18pi=a*17$

$a=18/17pi$

$a=3.33$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 36 36 and the height of the cylinder is 5 5 . If the volume of the solid is 18 pi18 pi, what is the area of the base of the cylinder?