A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 27 27 and the height of the cylinder is 11 11. If the volume of the solid is 120 pi120π, what is the area of the base of the cylinder?

1 Answer
May 2, 2017

The area is =18.8u^2=18.8u2

Explanation:

Let a=a= area of the base

Volume of cone is V_(co)=1/3*a*h_(co)Vco=13ahco

Volume of cylinder is V_(cy)=a*h_(cy)Vcy=ahcy

Total volume

V=V_(co)+V_(cy)V=Vco+Vcy

V=1/3ah_(co)+ah_(cy)V=13ahco+ahcy

120pi=a(1/3*27+11)120π=a(1327+11)

120pi=a*20120π=a20

a=120/20pia=12020π

a=6pia=6π

a=18.8u^2a=18.8u2