A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #39 # and the height of the cylinder is #17 #. If the volume of the solid is #60 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2018-07-28T02:30:28

#2\pi \ \text{unit}^2#

Ler #r# be the radius of common base of cylinder of height #17# & cone of height #39# then the total volume of the composite solid

#\pi r^2(17)+1/3\pir^2(39)=60 \pi#

#\pir^2(17+13)=60\pi#

#\pi r^2=\frac{60\pi}{30}#

#\pi r^2=2\pi#

#\text{Area of base of cylinder}=2\pi \ \text{unit}^2#