A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 39 and the height of the cylinder is 17 . If the volume of the solid is 60 pi, what is the area of the base of the cylinder?

1 Answer

2\pi \ \text{unit}^2

Explanation:

Ler r be the radius of common base of cylinder of height 17 & cone of height 39 then the total volume of the composite solid

\pi r^2(17)+1/3\pir^2(39)=60 \pi

\pir^2(17+13)=60\pi

\pi r^2=\frac{60\pi}{30}

\pi r^2=2\pi

\text{Area of base of cylinder}=2\pi \ \text{unit}^2