Question

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is `39` and the height of the cylinder is `17`. If the volume of the solid is `18 pi`, what is the area of the base of the cylinder?

Answer 1

`=0.6pi`

Explanation:

Volume of solid `V = Axxh_(cy)+1/3xxAxxh_(co)`
Where
Area of cylnder = area of cone = A
Height of cylinder =`h_(cy)=17`
Height of cone =`h_(co)=39`
Volume of the solid`V=18pi`
`:. 18pi= Axx17+1/cancel3xxAxxcancel39^13=30A`
`:. A= (18pi)/30=0.6pi`